Long Division with Polynomials
Introduction
I think this is a very manual process and easy to get wrong but I guess it at least follows a pattern. I would how much of this is required now.
Example 1
So getting more tricky below we need to follow a process. The question is
(x² + 5x + 6) / (x + 2)
So we put the denominator on the left like normal long division
----------------------------- (x + 2) | x² + 5x + 6
Step 1: Next we divide (x² + 5x + 6) by the first term only
x
-----------------------------
(x + 2) | x² + 5x + 6
Step 2: Next we need to multiply everything in the denominator by the result (top row) x and reverse the sign
x
-----------------------------
(x + 2) | x² + 5x + 6
-(x² - 2x)
Step 3: Now calculate the remainder by take one from the other
x
-----------------------------
(x + 2) | x² + 5x + 6
-(x² - 2x)
-----------------------------
0 + 3x + 6
No next we do steps 1-3 again,
Step 1: So x / 3x = + 3
x + 3
-----------------------------
(x + 2) | x² + 5x + 6
-(x² - 2x)
-----------------------------
3x + 6
Step 2: Next we need to multiply everything in the denominator by the result (top row) x and reverse the sign
x + 3
-----------------------------
(x + 2) | x² + 5x + 6
-(x² - 2x)
-----------------------------
3x + 6
-(3x +6)
-------
0
Step 3: Now calculate the remainder by take one from the other give 0
So we can say
(x² + 5x + 6) / (x + 2) = x+3
Example 2
So here is the next and shows you what to do when you have something left over. Here is the question and workings
2x³+8x²-6x+10 / x-2
2x²+12x+18+ 46/(x-2) -----------------------------
x-2 | 2x³+8x²-6x+10
-(2x³-4x²)
---------------
12x²-6x+10
-(12x²-24x)
-----------
18x+10
-(18x-36)
---------
46
So the answer is 2x²+12x+18 + 46 / x-2 left over.
Example 3
So the final example was
6x⁴-9x²+18 / x-3
The trick to this question to fill in the missing terms first
6x⁴+0x³-9x²+0x¹+18 / x-3
Filling in these means you can apply exactly the same steps