Imaginary And Complex Numbers - Revision history

Iwiseman: /* Solving Absolute Value of a Complex Number */

2026-04-26T03:43:20Z

Solving Absolute Value of a Complex Number

← Older revision		Revision as of 03:43, 26 April 2026
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	=Solving Absolute Value of a Complex Number=		=Solving Absolute Value of a Complex Number=
	So another remember the formula jobby. Standard form of a complex number is a+bi where a is the real number and b is the complete number. And the formula to working out the absolute value of a complex number is<br>		So another remember the formula jobby. Standard form of a complex number is a+bi where a is the real number and b is the complete number. And the formula to working out the absolute value of a complex number is<br>
	\| a + bi \| = <math>i = \sqrt{a^2 + b^2}</math>		\| a + bi \| = <math>i = \sqrt{a^2 + b^2}</math><br>
	So an example		So an example <br>
	\| 5 + 12i \| = <math>i = \sqrt{5^2 + 12^2}</math> = <math>i = \sqrt{25 + 144}</math> = <math>i = \sqrt{169}</math> = 13		\| 5 + 12i \| = <math>i = \sqrt{5^2 + 12^2}</math> = <math>i = \sqrt{25 + 144}</math> = <math>i = \sqrt{169}</math> = 13

Iwiseman: /* Solving Absolute Value of a Complex Number */

2026-04-26T03:43:04Z

Solving Absolute Value of a Complex Number

← Older revision		Revision as of 03:43, 26 April 2026
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	So another remember the formula jobby. Standard form of a complex number is a+bi where a is the real number and b is the complete number. And the formula to working out the absolute value of a complex number is<br>		So another remember the formula jobby. Standard form of a complex number is a+bi where a is the real number and b is the complete number. And the formula to working out the absolute value of a complex number is<br>
	\| a + bi \| = <math>i = \sqrt{a^2 + b^2}</math>		\| a + bi \| = <math>i = \sqrt{a^2 + b^2}</math>
			So an example
			\| 5 + 12i \| = <math>i = \sqrt{5^2 + 12^2}</math> = <math>i = \sqrt{25 + 144}</math> = <math>i = \sqrt{169}</math> = 13

Iwiseman: /* Solving Absolute Value of a Complex Number */

2026-04-26T03:39:53Z

Solving Absolute Value of a Complex Number

← Older revision		Revision as of 03:39, 26 April 2026
Line 13:		Line 13:
	=Solving Absolute Value of a Complex Number=		=Solving Absolute Value of a Complex Number=
	So another remember the formula jobby. Standard form of a complex number is a+bi where a is the real number and b is the complete number. And the formula to working out the absolute value of a complex number is<br>		So another remember the formula jobby. Standard form of a complex number is a+bi where a is the real number and b is the complete number. And the formula to working out the absolute value of a complex number is<br>
	\| a + bi \| =		\| a + bi \| = <math>i = \sqrt{a^2 + b^2}</math>

Iwiseman: /* Simplifying */

2026-04-26T03:39:04Z

Simplifying

← Older revision		Revision as of 03:39, 26 April 2026
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	<math>i^{33} = i^{32} . i^1</math> = <math>(1^4)^8 . i</math> = <math>i^8 . i</math> = i<br>		<math>i^{33} = i^{32} . i^1</math> = <math>(1^4)^8 . i</math> = <math>i^8 . i</math> = i<br>
	So I guess, get it down to a value you know and you are good to go		So I guess, get it down to a value you know and you are good to go
			=Solving Absolute Value of a Complex Number=
			So another remember the formula jobby. Standard form of a complex number is a+bi where a is the real number and b is the complete number. And the formula to working out the absolute value of a complex number is<br>
			\| a + bi \| =

Iwiseman: /* Simplifying */

2026-04-26T03:22:24Z

Simplifying

← Older revision		Revision as of 03:22, 26 April 2026
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	<math>i^7 = i^4 . i^3</math> = <math>1.(-i)</math> = i <br>		<math>i^7 = i^4 . i^3</math> = <math>1.(-i)</math> = i <br>
	<math>i^{33} = i^{32} . i^1</math> = <math>(1^4)^8 . i</math> = <math>i^8 . i</math> = i<br>		<math>i^{33} = i^{32} . i^1</math> = <math>(1^4)^8 . i</math> = <math>i^8 . i</math> = i<br>
			So I guess, get it down to a value you know and you are good to go

Iwiseman: /* Simplifying */

2026-04-26T03:21:41Z

Simplifying

← Older revision		Revision as of 03:21, 26 April 2026
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	So<br>		So<br>
	<math>i^7 = i^4 . i^3</math> = <math>1.(-i)</math> = i <br>		<math>i^7 = i^4 . i^3</math> = <math>1.(-i)</math> = i <br>
	<math>i^33 = i^32 . i^1</math> = <math>(1^4)^8 . i</math> = <math>i^8 . i</math> = i<br>		<math>i^{33} = i^{32} . i^1</math> = <math>(1^4)^8 . i</math> = <math>i^8 . i</math> = i<br>

Iwiseman: /* Simplifying */

2026-04-26T03:21:19Z

Simplifying

← Older revision		Revision as of 03:21, 26 April 2026
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	So<br>		So<br>
	<math>i^7 = i^4 . i^3</math> = <math>1.(-i)</math> = i <br>		<math>i^7 = i^4 . i^3</math> = <math>1.(-i)</math> = i <br>
			<math>i^33 = i^32 . i^1</math> = <math>(1^4)^8 . i</math> = <math>i^8 . i</math> = i<br>

Iwiseman: /* Introduction */

2026-04-26T03:18:30Z

Introduction

← Older revision		Revision as of 03:18, 26 April 2026
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	=Introduction=		=Introduction=
	So just trying to keep this stuff in my head. 42 years ago I was onto all this so let's see how we go. From memory is was a pretty easy ride. Just remember		So just trying to keep this stuff in my head. 42 years ago I was onto all this so let's see how we go. From memory is was a pretty easy ride. Just remember
	<math>i = \sqrt{-1}</math> <math>i^2 = -1</math> <math>i^3 = 1</math> and <math>i^4 = 1</math>		<math>i = \sqrt{-1}</math>
			<math>i^2 = -1</math>
			<math>i^3 = 1</math>
			<math>i^4 = 1</math>
			=Simplifying=
			So he gave examples and how he solved it an I guess most of the was just substitution and recognizing you can split exponent by adding e.g. <math>x^4 = x^3 . x^1</math><br>
			So<br>
			<math>i^7 = i^4 . i^3</math> = <math>1.(-i)</math> = i <br>

Iwiseman: /* Introduction */

2026-04-26T03:11:57Z

Introduction

← Older revision		Revision as of 03:11, 26 April 2026
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	=Introduction=		=Introduction=
	So just trying to keep this stuff in my head. 42 years ago I was onto all this so let's see how we go. From memory is was a pretty easy ride. Just remember		So just trying to keep this stuff in my head. 42 years ago I was onto all this so let's see how we go. From memory is was a pretty easy ride. Just remember
	<math>i = \sqrt{-1}</math>		<math>i = \sqrt{-1}</math> <math>i^2 = -1</math> <math>i^3 = 1</math> and <math>i^4 = 1</math>

Iwiseman: Created page with "=Introduction= So just trying to keep this stuff in my head. 42 years ago I was onto all this so let's see how we go. From memory is was a pretty easy ride. Just remember $i = \sqrt{-1}$ "

2026-04-26T03:10:58Z

Created page with "=Introduction= So just trying to keep this stuff in my head. 42 years ago I was onto all this so let's see how we go. From memory is was a pretty easy ride. Just remember <math>i = \sqrt{-1}</math>"

New page

=Introduction=
So just trying to keep this stuff in my head. 42 years ago I was onto all this so let's see how we go. From memory is was a pretty easy ride. Just remember
  <math>i = \sqrt{-1}</math>

Imaginary And Complex Numbers - Revision history

Iwiseman: /* Solving Absolute Value of a Complex Number */

Iwiseman: /* Solving Absolute Value of a Complex Number */

Iwiseman: /* Solving Absolute Value of a Complex Number */

Iwiseman: /* Simplifying */

Iwiseman: /* Simplifying */

Iwiseman: /* Simplifying */

Iwiseman: /* Simplifying */

Iwiseman: /* Introduction */

Iwiseman: /* Introduction */

Iwiseman: Created page with "=Introduction= So just trying to keep this stuff in my head. 42 years ago I was onto all this so let's see how we go. From memory is was a pretty easy ride. Just remember i = \sqrt{-1}"

Iwiseman: Created page with "=Introduction= So just trying to keep this stuff in my head. 42 years ago I was onto all this so let's see how we go. From memory is was a pretty easy ride. Just remember $i = \sqrt{-1}$ "