Polynomials
Introduction
So more stuff I probably know but here because I struggle with words.
Terms
These are mathematical expressions with consist of a Number and a variable for example 2x. The number part is called the coefficient which is a fancy way of saying the number you need to multiply by. The variable part can be a name and raised by a power.
Polynomial
A polynomial is a combination of many terms. e.g 2x²+3x+24. Each term must be joined by addition or subtraction not multiplication other binary operators. There are names for terms
- 1 term - monomial
- 2 terms - binomial
- 3 terms - trinomial
- More than 3 - polynomial
Examples
So some polynomial may not show the number or the variable part. For example
3x² + x -5
All this means is we have abbreviated the expression.
3x² + 1x -5x⁰
There now it looks proper. The last term which is just a number is known as the constant term as it never changes.
Degree of a term
The degree of a term is determined by the power of the variable part so given 2x²+3x+24
- 2x² 2nd degree term
- 3x 1st degree term
- 24 constant term
Where there are 2 variable we add them together 8x²y³ is a 5 degree term
People refer to the whole polynomial by the highest degree to 2x²+3x+24. So this is a 2nd degree polynomial. Polynomials are arranged by degree.
Simplifying Polynomials
So like terms can be added together
2x³+2x²+5x²+10
Can be
2x³+7²x+10
Long Division
Examle 1
So getting more tricky below we need to follow a process. The question is
(x² + 5x + 6) / (x + 2)
So we put the denominator on the left like normal long division
----------------------------- (x + 2) | x² + 5x + 6
Step 1: Next we divide (x² + 5x + 6) by the first term only
x
-----------------------------
(x + 2) | x² + 5x + 6
Step 2: Next we need to multiply everything in the denominator by the result (top row) x and reverse the sign
x
-----------------------------
(x + 2) | x² + 5x + 6
-(x² - 2x)
Step 3: Now calculate the remainder by take one from the other
x
-----------------------------
(x + 2) | x² + 5x + 6
-(x² - 2x)
-----------------------------
0 + 3x + 6
No next we do steps 1-3 again,
Step 1: So x / 3x = + 3
x + 3
-----------------------------
(x + 2) | x² + 5x + 6
-(x² - 2x)
-----------------------------
3x + 6
Step 2: Next we need to multiply everything in the denominator by the result (top row) x and reverse the sign
x + 3
-----------------------------
(x + 2) | x² + 5x + 6
-(x² - 2x)
-----------------------------
3x + 6
-(3x +6)
-------
0
Step 3: Now calculate the remainder by take one from the other give 0
So we can say
(x² + 5x + 6) / (x + 2) = x+3
Example 2
So here is the next and shows you what to do when you have something left over. Here is the question and workings
2x³+8x²-6x+10 / x-2
2x²+12x+18+ 46/(x-2) -----------------------------
x-2 | 2x³+8x²-6x+10
-(2x³-4x²)
---------------
12x²-6x+10
-(12x²-24x)
-----------
18x+10
-(18x-36)
---------
46
So the answer is 2x²+12x+18 + 46 / x-2 left over.
Example 3
So the final example was
6x⁴-9x²+18 / x-3
The trick to this question to fill in the missing terms first
6x⁴+0x³-9x²+0x¹+18 / x-3
Filling in these means you can apply exactly the same steps
Greatest Common Factor (GCF)
This is where you look at a polynomial and find, you guest it, the greatest common factor so given
3x + 15
It would be 3 because
3(x + 5)
And
4x² + 8x = 4x(x+2) GCF = 4x 5x² -15x³ = 5x²(1 -3x) GCF = 5x²
Factoring by Grouping
Here we divide the polynomial into two group and take out the GCF
x³ - 4x² + 3x -12
So group one
x³ - 4x² = x²(x-4)
Group two
3x -12 = 3(x - 4)
So they both have (x-4) so we can say
(x-4)(x² + 3)
Next example
2r³ -6r² + 5r - 15 = 2r²(r -3) +5(r -3) = (r-3)(2r² +5)
Factoring by Trinomials
For these you look for numbers which multiply to the constant and add up to the coefficient of the x term
x² + 3x - 28
So in the case two numbers which multiply to -28 and add up to +3
So 28 factors are 1, 28, 2, 14, 7, 4 - so 7 and 4
(x -4)(x+7)
And given
x² - 3x - 10
So factors of 10 are 1,10,2,5 - so 5 and 2
(x-5)(x+2)
When the first term is not x² for example
2x² + 20x + 48
Just get rid of the 2
2(x² + 10x + 24) 2(x+4)(x+6)
What do you do I you cannot factor out to x². A tiny bit more complex this bit because the slight of hand of the youtuber. You need to multiply the coefficient of the first term with the constant and then look for two numbers which when added together = the middle term. So given
2x² - 5x + -3
So 2x -3 = -6 and factors of -6 are 2, -3, 1 -6
So 1 -6 = -5 = the middle term coefficient<br
And this was the tricky bit. Just replace p-5x with -6x +1x. It is obvious when you see it but they mean replace the middle term with the factors you identified. In this case 1 and -6. So we have
2x² - 6x + 1x -3
So using the grouping approach take out the GCF we have
2x(x-3) + 1(x-3) (x-3)(2x+1)
Perfect Square Trinomial
Intro
This was the bane of my life today and hopeful will be clear as day from now on. The perfect square trinomial is of the form
A² + 2AB + B² = (A+B)²
And this is the bit I needed. If you take square root term 1, and term 3 and multiply them by 2 and it equals term 2 you are golden.
So for example
x² + 8x + 16
Using the approach from above rather than perfect square, by grouping we can see factors of 16 which = 8 are 4,4 and so
(x+4)(x+4) = (x+4)²
Using the perfect square approach we do
Square root of x² = x Square root of 16 = 4 Middle term is 2(4x)
Not a Perfect Square
So here is one which is not. This was the tutors step by step
9x² + 6x + 4 Square root of 9x² = 3 Square root of 4 = 2 3x2 = 6 but we have to double it because it is 2(AB) = 12 so not a perfect square
Is a Perfect Square
And a good one
4x² + 12x + 9 Square root of 4x² = 2 Square root of 9 = 3 3x2 = 6 but we have to double it because it is 2(AB) = 12 so is a perfect square Looking what makes 4x² is 2x and what makes 9 is 3 so answer is (2x+3)²
Difference in Squares
So if we want to do difference in square A²-B² = (A+B)(A-B). Needed to understand the (A+B)(A-B) so
= (A+B)(A-B) = A² - AB + BA + B²
Now -AB + AB = 0 So
= A² - B²
So looking at some examples
x² - 25 = (x+5)(x-5) x² - 36 = (x+6)(x-6) 4x² - 9 = (2x+3)(2x-3)